if a ball is kicked from the ground such that it has an initial vertical velocity of 10 m/s and an initial horizontal velocity of 3.0 m/s, how far away will it be when it hits the ground for the first time after the kick?

The ball will go till a distance of 0.066 meters before hitting the ground for the first time.The initial vertical velocity of the ball is 10m/s and the initial horizontal velocity of the ball is 3m/s.The path of the ball will be a projectile.The horizontal range of the projectile is given by,R = u²2cosAsinA/gu is the initial velocity,g is acceleration due to gravity,.tanA = 10/3Perpendicular = 10Base = 3Hypotenuse = 10.44sinA = 10.44/10cosA = 3/10u = √(10)²+(3)²u = 10.44m/s.Putting the values,R = 10.44 x 2 x 10.44/10 x 3/10 x 1/9.8R = 0.066 meters.The ball goes 0.066 meters far.To know more about Projectile motion, visit,https://brainly.com/question/24216590#SPJ4