a person lifted the barbell from the ground. the mass of the barbell was 100 kg. it took him 0.5 seconds to move the barbell through a vertical displacement of 1.5 m. what was the average power output during the lift (g

The average power output during the lift is 2940w.Given, a person lifted the barbell from the ground.The mass of the barbell = 100kg time taken = 0.5s displacement = s = 1.5m we know,w = mgs = 100 × 0.5 × 1.5 = 1470jAs we know ,power = work done / unit timeP = 1470j/0.5s = 2940wHence,the average power output during the lift is 2940w.what is power? Power is always a function of labour output, therefore if a person works at a variable rate depending on the time of day, his power will likewise vary. The idea of average-power enters the picture at this point. Let's study about power, average power, unit, and formula in this session.Average power is calculated by dividing the total energy used by the total time required. The average quantity of work completed or energy converted per unit of time is known as average power.The rate at which work is performed on an object is referred to as its power. Power is a temporal concept. It has to do with how quickly a task gets completed.Learn more about power here :brainly.com/question/7007759#SPJ4