a 1125 kg car and a 2250 kg pickup truck approach a curve on a highway that has a radius of 225 m. (a) at what angle should the highway engineer bank this curve so that vehicles traveling at 65 mph can safely round it regardless of the condition of their tires?

The angle is 21.0°.What is Angle?When two straight lines or rays intersect at a single endpoint, an angle is created. The vertex of an angle is the location where two points come together.Given:R = 225m[tex]m_{c}[/tex] = 1125kg,​ [tex]m_{t}[/tex]=2250kg​v = 65mph = 29.1m/sg = 9.8 m/s²It is necessary to use the formula below in order to correctly manipulate these numbers:[tex]a_{rad}[/tex] = v²/Ra) [tex]\sum F_{x} =nsin\theta = ma_{rad}[/tex][tex]\sum F_{y} = ncos\theta+ (-mg) =0[/tex]The centripetal acceleration, a rad = dfracv2, and the horizontal component of the normal force are both present in the acceleration in the x-direction. [tex]a_{rad}[/tex] =v²/R. Since there should be no acceleration in the y-direction (i.e., no slipping off the road), the y-component is set to zero. The acceleration in the y-direction is the result of adding the vertical component of the normal force with the acceleration caused by gravity.solving [tex]\sum F_{y}[/tex] for n yields n = mg/cosθSubstituting this into [tex]\sum F_{x}[/tex] using [tex]a_{rad}[/tex] = v²/Ryields mg/cosθ ×sinθ = mv²/Rsolving for θ yields tanθ = v²/gR (or) θ = [tex]a_{rad}[/tex] v²/gRAs a result, the angle solely depends on the curve's radius and speed. The results are obtained by incorporating those values with the gravitational acceleration constant.[tex]a_{rad}[/tex] (29.1)²/22.5×9.8 = [tex]a_{rad}[/tex] (0.384) = 21.0°.To know more about angles visit:https://brainly.com/question/28451077#SPJ4