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The cylinder's length is x = 111.94 cm, for the H2 gas and L - x = 120 - 111.94 = 8.055 cm for the N2 gas.Which is the ideal gas law?The ideal gas law (PV = nRT) connects the macroscopic characteristics of ideal gases. An ideal gas is one in which the particles are both non-repellent and non-attractive to one another (have no volume).Given,The length of the cylinder, L = 120 cmThe mass of the N2 = mnN2 has a molecular weight of Mn = 28.013 g/mol.The molecular mass of H2, Mh = 2.016 g/molThe mass of the H2 = mh.The universal gas constant = RuWe shall assume that the behavior of both gases (N2 and H2) is perfect. It applies the ideal gas law.P.V = n. Ru. TThe relationship between a gas's mass in kilogrammes and molecular weight determines how many moles (n) there are of that gas ( Mr ). Done by:n = m/[tex]M_{r}[/tex]In the equation for the ideal gas state, substitute the number of moles. To date,P.V = m/[tex]M_{r}[/tex]. Ru. TThe pressures, masses, and temperatures of the gases are now equal based on the available data. So, for each gas, we will create the two state equation.N₂P.Vₙ = m/[tex]M_{r}[/tex]. Ru. TH₂P.[tex]V_{h}[/tex] = m/[tex]M_{r}[/tex]. Ru. TDistinguish between the two gases' state equations (N₂/H₂),Vₙ/[tex]V_{h}[/tex] = [tex]M_{h}[/tex]/Mₙ = 2.016/28.013 = 0.07196We'll suppose that the cylinder's cross-sectional area, "A," remains constant along its length. Therefore, "x" for one-dimensional length designates the length of the cylinder in which the H2 gas is contained.The N2 gas fills the remaining length "L - x," hence we have:Vₙ/[tex]V_{h}[/tex] = π.r².(L - x)/π.r².(x) = L - x/xThe estimated ratio is now equal to:Vₙ/[tex]V_{h}[/tex] = L - x/x = 0.07196L - x = 0.07196xL = 1.07196xx = 120/1.07196x = 111.94cm.The cylinder's length is x = 111.94 cm for the H2 gas and L - x = 120 - 111.94 = 8.055 cm for the N2 gas.To know more about ideal gas law visit:https://brainly.com/question/28257995#SPJ4
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