If the pressure in a hydraulic press is increased by an additional 10 n/cm2, how much extra load will the output piston support if its cross-sectional area is 50 cm2?.

The pressure given is P = 10N/cm² The cross sectional area is A = 50cm² Formula ,P = Force / AreaF = P X AF = ( 10N/cm² ) X ( 50cm² )F= 500NThe machines you might have seen are used for crushing cars, molding and casting metal objects, and a whole host of other applications. Any kind of work that involves the application of high pressure over a finite and small area is the perfect job for the hydraulic press. The hydraulic press depends on Pascal's principle: the pressure throughout a closed system is constant.Since the development of the Bramah Hydraulic Press, the hydraulic press has rapidly improved and advanced to become a highly technical tool that can provide precision and accurate deforming of materials.Hence extra load will the output piston IS 500NTo know more about Hydraulic press from the given link:https://brainly.com/question/857286#SPJ4