the wheels of a car are locked as it slides to a stop from an initial speed of 30 m/s. if the coefficient of kinetic friction is 0.600 and the road is horizontal, approximately how long does it take the car to stop?

It take 5.10 s for the car to stopIt is Given thatInitially moving at 30 m/sThe vehicle had been stopped, thus0 m/s, or final velocityuk = 0.600 for the coefficient of kinetic friction.Time it took the automobile to stop, t =?First, we calculate the friction-induced deceleration (negative acceleration), "a"a = -uk * ga = -0.600 x 9.81m/s²a = -5.88m/s²Now, using the first equation of motion:v = u + atWhere v is the final velocity, u is the initial velocity, a is the acceleration and tis the time taken.We substitute our values into the equation0 m/s = 30.0m/s + (-5.88m/s² * t)(5.88m/s² * t) = 30m/st = 30m/s / 5.88m/s² t = 5.10sGiven the coefficient of kinetic friction and the initial velocity, the time taken for the car to come to a stop is approximately 5.10 seconds.Hence, it take 5.10 s for the car to stopLearn more about Time here:https://brainly.com/question/26046491#SPJ4