a machine gun, of mass 35.0 kg, fires 50.0-gram bullets, with a muzzle velocity of 750 m/s, at the rate of 300 rounds per minute. what is the average force exerted on the machine gun mount?

Force exerted on the machine gun is 187.5 NMass of gun = 35.0 kgMass of bullets = 50 gramVelocity of bullets = 750 m/sNumber of bullets fired/second = 300We know, F = rate of change in linear momentumF = Change in linear momentum/timeIn t = 1 s, total mass of bullets fired60 sec = 300 bullets1 sec = 300/60 = 5 bullets50 x 5 = 250 gram = 250 x 10^-3 kgSo, F = 250 x 10^-3 kg x 750/1F = 187.5 NHence, force exerted on the machine gun is 187.5 NLearn more about Force here:https://brainly.com/question/12785175#SPJ4