A basketball is thrown horizontally with an initial speed of 3 m/s. a straight line drawn from the release point to the landing point makes an angle of 30.0 degrees with the horizontal. what was the release height?

The release height of the basketball is 0.05 m.Projectile motion is a form of movement skilled by way of an item or particle that is projected in a gravitational area, which includes from Earth's floor, and actions alongside a curved route below the movement of gravity most effective.Projectile motion is the motion of an item thrown (projected) into the air. After the initial force that launches the object, it best experiences the pressure of gravity. The item is known as a projectile, and its course is known as its trajectory.The course of a projectile is parabolic. for the duration of the movement, the acceleration of the projectile is regular and acts vertically downwards being equal to g. The angular momentum of projectile = mu cos Θ × h wherein the price of h denotes the height.calculation:-angle with vertical  = 30°So, the angle with the vertical = 60°horizontal velocity = 3 cos 30° m/svertical velocity = 3 sin 30°  m/s  = 2 × 1/2                           = 1 m/sFor height V² = U² -2aS                 0 = 1² - 2 ×9.8 × S S = 1/19.6    = 0.05 mLearn more about Projectile motion here:-https://brainly.com/question/10680035#SPJ4