An electron with an initial speed of 340,000 m/s
m
/
s
is brought to rest by an electric field.

Answer:0,33  VoltExplanation:v = 340 000 m/s - Initial electron speedm = 9.1·10⁻³¹ kg - Mass of an electronW = m·v² / 2 - Initial kinetic energy of an electronW = 9.1·10⁻³¹·(340 000)² /2 ≈ 5.26 · 10⁻²⁰ J       (1)Q = 1.6·10⁻¹⁹  C  - Electron charge modulusThe work of the electric field:A = Q·V   (2)  Equate (2) and (1):Q·V = WV - Electric field potential difference V = W / Q = 5.26 · 10⁻²⁰ / 1.6·10⁻¹⁹ ≈ 0,33  Volt