A ball is launched with an initial horizontal velocity of 10.0 meters per second. It takes 500 milliseconds for the ball to reach its maximum height.
a. Determine the maximum horizontal distance
that the ball will travel.
b. Calculate the initial vertical velocity of the ball.
HELPP ASAPP!!!!!!

a) The maximum horizontal distance that the ball will travel will be  10 mb) The initial vertical velocity of the ball will be 4.9 m/s a) initial horizontal velocity = u(x) = 10.0 m/stime = 500 * [tex]10^{-3}[/tex] sec = 0.5 sec at maximum height final horizontal velocity = 0horizontal velocity = time of flight * u(x) = 2t * u(x) = 2 * 0.5 * 10 = 10 mb) initial vertical velocity = ?final vertical velocity = initial vertical velocity - g*tusing kinematic equation : 0 = u (y) - 9.8 * 0.5u(y) = 4.9 m/s To learn more about kinematic equation here :https://brainly.com/question/28712225#SPJ1