A uniform bar has two small balls glued to its ends. The bar is 3.5 m long and has mass 2.6 kg, while the balls each have mass 0.5 kg and can be treated as point masses. Find the moment of inertia of this combination about an axis perpendicular to the bar and through one of the balls.

The moment of inertia of this combination about an axis perpendicular to the bar and through one of the balls is 5.71 kgm².What is moment of inertia?The moment of inertia is a measure of how resistant an object is to changes in its rotational motion.The moment of inertia of any object is obtained from the product of mass and square of radius of the object.Mathematically, the moment of inertia of the rod and the points masses is calculated by apply the following equation.I = ¹/₁₂ML²  +  2m(L/₂)²where;M is the mass of the rodm is the mass of the ballsL is the length of the rodThe moment of inertia of this combination about an axis perpendicular to the bar and through one of the balls is calculated as follows;I = ¹/₁₂(2.6)(3.5)²  +  2(0.5)(3.5/₂)²I = 2.65 + 3.0625I = 5.71 kgm²Learn more about moment of inertia here: https://brainly.com/question/3406242#SPJ1