An Air Force jet flying with a speed of 335 m/s went pass an anti aircraft gun.how far is the aircraft 5s later when the gun was fired

The aircraft after 5s later when the gun was fired was at a distance of 1675m flying with a speed of 335m/s. Air force jet was flying with a speed of 335m/s and at that time gun was fired by anti aircraft.The formula of speed is S= distance(d)/time(t)The unit of distance is in meters, Speed is in meter/secondTime is in secondsSubstituting the values given in this equation335m/s= d/5sd= 335*5 d= 1675mThus, after 5 seconds from the gun fired by anti aircraft, the airforce jet will be 1675m far.For more information on speed kindly visit tohttps://brainly.com/question/863940