Find the direction of the sum of
these two vectors:
B 3.14 m 2.71 m 30.0°
-60.0°A direction (deg)

The magnitude and direction of the sum of vectors will be 4.15 m aligned in  50° in north west direction.Both the vectors are making angle in a way that it will add up to 90° , hence a right angles triangle will be formed .using Pythagoras theorem [tex]H^{2} = P^{2} + B^{2}[/tex]sum of vector = [tex]H^{2} = P^{2} + B^{2}[/tex]H = [tex]\sqrt{P^{2} + B^{2} }[/tex]    = [tex]\sqrt{3.14^{2} + 2.71^{2} }[/tex]    = 4.15  mlet theta is the angle along the base vector 2 tan (theta ) = P/B = 3.14 / 2.71 = 1.16 °theta = [tex]tan^{-1}[/tex] ( 1.16 )          ≈ 50° hence , The magnitude and direction of the sum of vectors will be 4.15 m aligned in  50° in north west direction.To learn more about vector here :https://brainly.com/question/13322477#SPJ1