Two Liquids, A and B, are mixed. A is 5% solids, the rest is water. B is 11% solids; the rest is water. To the mixture is added 18.5 kg of bone-dry solids resulting in a mixture of 2,150 Kg containing 8.25% solids. What were the original amounts of the liquids A and B? Show all work

The original amounts of the liquids A and B based on the information will be 1260kg and 872kg.What is an equation?An equation is the statement that illustrates that the variables given. In this case, two or more components are taken into consideration to describe the scenario. It is vital to note that an equation is a mathematical statement which is made up of two expressions that are connected by an equal sign.Based on the information given, let us call the liquids illustrated as A and B, while the weight is in kg.The first equation is the amount of solids and this will be represented thus:0.05A + 0.11B + 18.5 = 0.0825(2150) = 177.3750.05A + 0.11B = 158.8755A + 11B = 15887.5The second equation will be represented thus:A + B + 18.5 = 2150Collect like termsA + B = 2150 - 18.5A + B = 2131.5Multiplying the equation will be:6B = 5230Divide through by 66B / 6 = 5230 / 6B = 872 kgTherefore, A will be 1260 kg.Learn more about liquid on:https://brainly.com/question/752663#SPJ1