A child throws a piece of candy corn directly up with an initial velocity of 3.8 m/s. If the starting height of the candy was 2.2 meters, what will be the height of the candy after 0.3 seconds? Use a = -9.8m/s/s

Answer:2.89855 metersSteps:Let’s use theΔx = Vi * t + 1/2 * a * t^2Δx is short for change in position thereforeXf - Xi = Vi * t + 1/2 * a * t^2We are given the initial position, initial velocity, acceleration, and time. Let’s solve for final position (Xf).Xf - 2.2 = 3.8 * 0.3 + 1/2 * -9.81 * 0.3^2Xf - 2.2 = 1.14 + 1/2 * -9.81 * 0.3^2Xf - 2.2 = 1.14 + -4.905 * 0.09Xf - 2.2 = 1.14 + −0.44145Xf - 2.2 = 1.14 - 0.44145Xf - 2.2 = 0.69855Xf = 0.69855 + 2.2Xf = 2.89855