Find the work done in moving a particle from P (0.92, 2.5) to Q(−3.1, 5) if the force is ⃗v = −3.6ˆı + 2.1ˆ.

The magnitude of the work done on the particle by the applied force is 19.72 J.What is work done?The work done in moving a charged particle is determined from the product of force and displacement of the object.W = Fdwhere;F is the applied forced is the displacement of the particleThe magnitude of the particle's displacement is calculated as follows;|d| = √[(x₂ - x₁)² + (y₂ - y₁)²]where;x₁ and x₂ are the initial and final position of the particle in horizontal directiony₁ and y₂ are the initial and final position of the particle in vertical direction|d| = √[(-3.1 - 0.92)² + (5 - 2.5)²]|d| = 4.73 mThe magnitude of the force is calculated as follows;F = √(-3.6² + 2.1²)F = 4.17 NThe work done = 4.17 N x 4.73 m = 19.72 JLearn more about work done here: https://brainly.com/question/8119756#SPJ1