A girl riding a bicycle at 2.0 m/s throws a tennis ball horizontally forward at a speed of 1.0 m/s from a height of 1.5 m. At the same moment, a boy standing on the sidewalk drops a tennis ball straight down from a height of 1.5 m.What is the initial speed of the girl's ball relative to the boy? ​WILL GIVE BRAINLIEST

The initial speed of the girl's ball relative to the boy is 3 m/s. ​What is the initial speed of the girl's ball?The initial speed of the girl's ball relative to the boy depends on the time of motion of the girls ball.The time of motion of the ball from the given height is calculated as follows;h = vt + ¹/₂gt²wherev is the initial velocity of the ballt is the time of motion of the ballg is acceleration due to gravityh = 0 + ¹/₂gt²h = ¹/₂gt²t = √(2h/g)t = √(2 x 1.5 / 9.8)t = 0.55 sThe final velocity of the ball is calculated as;v = gtv = 9.8 x 0.55v = 5.39 m/sHowever, since we are looking for the initial speed of the girl's ball relative to the boy, we will ignore the final velocity of the ball.The initial velocity of the ball = 0The initial velocity of the girl's ball = 2 m/s + 1 m/s = 3 m/sThe relative velocity = 3 m/s - 0 m/s = 3 m/sLearn more about relative velocity here: https://brainly.com/question/17228388#SPJ1