A block of mass m1 = 14.4 kg is on a frictionless table to the left of a second block of mass m2 = 20.2 kg, attached by a horizontal string (see the figure below).
(a) If a horizontal force of 1.53 ✕ 102 N is exerted on the block m2 in the positive x-direction, use the system approach to find the acceleration (in m/s2) of the two blocks.
(b) What is the tension (in N) in the string connecting the blocks?

(a) The acceleration (in m/s²) of the two blocks is 4.42 m/s².(b) The tension (in N) in the string connecting the blocks is 63.65 N.What is the acceleration of the blocks?The acceleration of the blocks is determined by applying Newton's second law of motion as shown below.F(net) = mawhere;F(net) is the net force on the blocksm is the mass of the blocksa is the acceleration of the blocksF = m₁a + m₂aF = a(m₁ + m₂)a = F/(m₁ + m₂)where;a is the common acceleration of the blocksm₁ is the mass of the first block = 14.4 kgm₂ is the mass of the second block = 20.2 kgF is the applied force on the blocks = 153 Na = (153) / (14.4 + 20.2)a = 4.42 m/s²The tension (in N) in the string connecting the blocks is calculated as follows;T = m₁aT = 14.4 x 4.42T = 63.65 NLearn more about tension in strings here: https://brainly.com/question/24994188#SPJ1