how large an angular acceleration must a wheel have is it is to acceleration from rest to 460rad/s after 5rev ?​

Answer:Explanation:Given:φ₀ = 0 radω₀ = 0 rad/sω = 460 rad/sN = 5 rev; φ = 2π·N= 2·3.14·5 = 31.4 rad________________ε - ?ω = ω₀ + ε·tt = (ω - ω₀) / ε = (3.14 - 0) / ε = 3.14/εφ = φ₀ + ω₀·t + ε·t² / 23.14 = 0 +0·t + ε·3.14² / (2·ε²)3.14 = 3.14² / (2·ε)1.00 = 3.14 / (2·ε)ε = 3.14 / 2 ≈ 1.57 rad/s²