The toy car in Figure 20 runs off the edge of a table that is 1.225m high. The car lands 0.4000m from the base of the table. Show all work.
How long did it take the car to fall?

The time taken for the toy car to fall from the given height is 0.5 second.What is the time of motion of the toy car?The time of motion of the toy car is calculated by applying the following equation as shown below.h = vt + ¹/₂gt²where;h is the vertical height of fall of the toy carv is the initial vertical velocity of the toy cart is the time of motion of the toy carg is acceleration due to gravity = 9.8 m/s²The initial vertical velocity of the toy car = 0h = 0 + ¹/₂gt²h = ¹/₂gt²2h = gt²t² = 2h/gt = √(2h/g)t = √(2 x 1.225 / 9.8)t = 0.5 secondLearn more about time of motion here: https://brainly.com/question/2364404#SPJ1