To cool 350 mL of coffee at 90 ∘C to 0 ∘C , what is the minimum mass of 0 ∘C ice required?

Ice at 0°C must have a minimum mass of 0.39 kg.As we know thatM(ice) at Ti(ice) = 0°CMс = 350 ml at Tic = 90°CNow,The heat loss by coffee=heat gain by iceSo,McScΔ₁ = M₁L₁Then, ρv = 10³×(350×10-³)×10-³ = 350gThe specific heat of coffee = 1 cal/9°CThe latent heat of ice = 80 cal/g Now, we plug all the values in above formula350×1×(90-0) - M₁x80M₁ = [tex]\frac{350x90}{80}[/tex]     =393.75g     =0.393kg The minimum mass of 0°C ice required is 0.393 kilogramsLearn more about latent heat at: https://brainly.com/question/27997708