A golf ball is thrown straight up in the air at a velocity of 8.3 . Determine the maximum height of the golf ball.
(b) How long will it take the ball to reach its maximum height?
(c) How long will it take the ball to fall from its maximum height to the height from which it was initially launched?

a) The maximum height is 3.5 mb) The time taken to reach this height is 0.85 secondsc) The time taken to return to the original point is 0.85 seconds.What is the maximum height?We know that the maximum height can be obtained from the use of the kinematic equations. We know that;a) v^2 = u^2 - 2ghv = final velocityu = initial velocityg = acceleration due to gravityh = maximum height attainedv= 0 /ms at the maximum heightu^2 = 2ghh = u^2/2gh = (8.3)^2/2 * 9.8h = 68.89/10.6h = 3.5 mb) Time taken to reach the maximum height;v = u - gtv= 0 /ms at the maximum heightu = gtt = u/gt = 8.3/9.8t = 0.85 secondsc) The time taken to return is the same as the time taken to go up which is 0.85 seconds.Learn more about kinematics:https://brainly.com/question/7590442#SPJ1