Suggested Answer
Answer:In this question, we have given a basketball hoop that is 3.05 m above the playing surface and the basket is made. The basketball was launched from a height of 1.95 And if the ball travels the original distance of 5.2 m in two seconds, then we have to find the initial velocity of the basketball. So we can find given data is we have given the horizontal distance traveled, that is d is equals to 5.2 m Per meter. And we have given the time taken to cover this distance, that is T equals to two seconds. So we can find the original velocity. So we can see that horizontal velocity that is three X is equal to, this is 5.2 upon two, and this will come out to be 2.6 meter per second. Now we can see that as we have given That the basketball hoop is 3.05 m above the playing surface. So we can say that the height covered, that is delta edges 3.5 minus 1.95. And this will comes out to be 1.10 m. So, using the equation of motion, we can find the vertical velocity Y. So we can say that that is is, we can apply in and wind direction. So we can say that delta edge is equals to this is initial velocity in y direction into time, T plus half into exhalation in y direction into T square. So we can say this is equals to 1.10, that is we're not y and to time is two seconds blood half into disease. Here, exploration is the gravitational acceleration and it is acting downwards. So this is equal to -3, which is -9.8 into two square. So from here we can find the value of velocity in the Y direction. That is 10.35 m/s. So we have the velocity in X direction and velocity in the Y direction. So we can see that the initial velocity that is we note is equal to this under root of we're not in extraction plus we're not wise square. So we can say this is equal to under root of 2.60 sq Plus 10.35 ft sq. And this will comes out to be 10.67 m/s. But this is the answer of arguing cushion. Thank you.
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