Determine the net capacitance C of each network of capacitors shown below. Assume that C1=1.0pF, C2=2.0pF, C3=4.0pF, and C4=5.0pF

The net capacitance C of each network of capacitors is 7.33 pF.What is the net capacitance of series capacitors?The net capacitance of a circuit containing capacitors arranged in series to one another is the reciprocal sum of the individual capacitance.Mathematically, this capacitance is given as;1/Ct = 1/C₁ + 1/C₂ + 1/C₃ + 1/C₄ + 1/C₅where;Ct is the net capacitance C is the individual capacitanceThe capacitance of capacitors arranged in parallel to one another, the net capacitance is the sum of the individual capacitors.Ct = C₁ + C₂ + C₃ + C₄ + C₅In the given circuit, the net capacitance is calculated as follows;C₂  and C₃ are in series to one another, the net capacitance of these two is calculated as;1/Ct = 1/C₂ + 1/C₃1/Ct = 1/2 + 1/41/Ct = 3/4Ct = 4/3 pFCt = 1.33 pFCombining the whole capacitors in the circuit, C₂, C₃ are in parallel with C₁ and C₄Ct = 1.33 pF + C₁ + C₄Ct = 1.33 pF   +  1 pF   +   5 pFCt = 7.33 pFLearn more about net capacitance here: https://brainly.com/question/27753307#SPJ1