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The temperature at which the bar will fit exactly into a hole of constant width 10.005 cm if coefficient of linear expansion of steel is 11x10-6 C-1 is 95.5 °CΔ L = L - LoΔ T = T - To Δ L = Change in lengthL = Initial lengthLo = Final lengthα = Co-efficient of linear expansionΔ T = Change in temperature T = Initial temperatureTo = Final temperatureL = 10 cmLo = 10.005 cmT = 50 °CΔ L = - 0.005 cmα = 11 * [tex]10^{-6}[/tex] / °CΔ L / L = α Δ TΔ L / α L + T = ToTo = ( - 0.005 ) / 11 * [tex]10^{-6}[/tex] * 10 + 50To = 45.5 + 50To = 95.5 °CTherefore, the temperature at which the bar will fit exactly into a hole is 95.5 °CTo know more about coefficient of linear expansionhttps://brainly.com/question/14780533#SPJ1