Accepted Answer
The time taken for the bowling ball to stop, given that a force of 38 N was applied is 0.55 sHow to determine the timeWe'll begin by obtaining the deceleration of the ball. This can be obtained as follow:Weight of ball (W) = 68 NAcceleration due to gravity (g) = 9.8 m/s²Mass (m) = W / g = 68 / 9.8 = 6.9 KgForce (F) = 38 NDeceleration (a) = 5.71×10¹⁴ Force (F) = mass (m) × deceleration (a)F = maDivide both sides by ma = F /ma = 38 / 6.9a = -5.5 m/s² Finally, we shall determine the time. This is shown below:Initial velocity (u) = 3.00 m/sDeceleration (a) = -5.5 m/s² Final velocity (v) = 0 m/sTime (t) =? a = (v – u) / t-5.5 = (0 – 3) / t-5.5 = -3 / tCross multiply-5.5 × t = -3Divide both sides by -5.5 t = -3 / -5.5 t = 0.55 sThus, we can say that the time required is 0.55 sLearn more about time:https://brainly.com/question/13257215https://brainly.com/question/17146782#SPJ1
Related Question in Physics
