An 80kg woman jumps from a wall and lands stiff-legged in soft sand. The woman's downward speed just as she touches the sand is 6m/s. She is stopped after sinking 0.05m into the sand. Calculate the net force on the woman while she is being stopped by the sand. Round to nearest whole number

The net force on the woman while she was stopped by the sand is 28800 N.What is force?Force can be defined as the product of the mass of a body and its acceleration.To calculate the net force on the woman, we use the formula below.Formula:F = m(v²-u²)/2s........... Equation 1Where:m = Mass of the womanF = Force on the womanv = Final velocityu = Initial velocitys = DistanceFrom the question,Given:m = 80 kgv = 6 m/su = 0 m/ss = 0.05 mSubstitute these values into equation 1F = 80(6²-0²)/(2×0.05)F= 80×36/0.1F = 28800 NHence, the  net force on the woman is 28800 N.Learn more about force here: https://brainly.com/question/25239010#SPJ1