A worker lifts a 10 kilogram block a vertical height of 2 meters. The work he does on the block is:

So yeah I think it’s this

Answer:Work = 196 Joules (1 kg*m^2/sec^2 is 1 Joule)Explanation:Work, W, is defined as force. F, times displacement, d.     W = Force*displacementIn the worker's case, the force he/she is struggling against is Earth's gravity's acceleration, g, (9.8 m/sec^2) times the mass, m.Force = mgForce = (10kg)*(9.8 m/sec^2) = 98 kg*m/sec^2Use this force in the work calculation.W = Force*displacementThe displacement is 2 meters.Work = (98 kg*m/sec^2)*(2 meters) = 196 kg*m^2/sec^21 kg*m^2/sec^2 is 1 JouleWork = 196 Joules