The figure shows an overhead view of a 1.40 kg plastic rod of length 1.20 m on a table. One end of the rod is attached to the table, and the rod is free to pivot about this point without friction. A disk of mass 38.0 g slides toward the opposite end of the rod with an initial velocity of 35.5 m/s. The disk strikes the rod and sticks to it. After the collision, the rod rotates about the pivot point.
A thin vertical rod has a point labeled pivot at its bottom, and a disk moving horizontally along an arrow labeled vector v that will reach the rod perpendicularly at the top.
(a) What is the angular velocity, in rad/s, of the two after the collision?

The angular velocity, in rad/s, of the two after the collision is 28.7 rad/s.What is the angular velocity after collision?The angular velocity, in rad/s, of the two after the collision is determined by applying principle of conservation of angular momentum as follows;I₁ω₁ = I₂ω₂where;I₁ is the initial moment of inertia of the rodI₂ is the final moment of inertia of the rodω₁ is the initial angular speed of the diskω₂ is the final angular velocity of the system after the collisionInitial moment of inertia of the rod is calculated as follows;I₁ = ¹/₃ML²where;M is mass of the rodL is length of the rodI₁ = ¹/₃ x 1.4 x (1.2²)I₁ = 0.67 kgm²Final moment of inertia of the rod is calculated as;I₂ = ¹/₃ x (1.4 + 0.038) x (1.2²)I₂ = 0.69 kgm²I₁ω₁ = I₂ω₂0.67(0 + 35.5/1.2) = 0.69ω₂19.82 = 0.69ω₂ω₂ = 19.82/0.69ω₂ = 28.7 rad/sLearn more about angular momentum here: https://brainly.com/question/7538238#SPJ1