It takes 6 people pulling with a force of 500. N each to begin moving the opposing team which was pulling with a combined force of 2500. N during a match of tug-of -war. If the total mass of both teams was 2000. kg, what was the force due to static friction? HELP ME .

From the calculations, we have the coefficient of friction as  0.026.What is the coefficient of static friction?We know that friction has to do with the force that tends to oppose the motion of an object. As such, the point where the force of friction acts is actually the surface that lies between two bodies.Now, we can see that It takes 6 people pulling with a force of 500 N each to begin moving the opposing team which was pulling with a combined force of 2500 N. This implies that the total force of the people that are pulling from this other side is 6 (500N) = 3000 NNow we have the net force that is acting on the the rope as; 3000 N - 2500 N = 500 NThen;Coefficient of friction = Net force/ Normal reaction = 500 N/(2000 * 9.8) N= 0.026Learn more about Coefficient of friction:https://brainly.com/question/13754413#SPJ1