This is a statistics/applications question

[SOLVED] This is a statistics/applications question
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Using percentages, the answer to all the subparts are shown:(A) % who scored between 46 and 106: 67% approx(B) % who scored less than 46: 17% approx(C) % who scored between 61 and 91: 33% approx(D) % who scored between 76 and 121: 50%What are percentages?The area of mathematics known as probability deals with numerical representations of the likelihood that an event will occur or that a statement is true. By dividing the value by the entire value and multiplying the result by 100, one may determine the percentage. The percentage calculation formula is (value/total value)100%.So, calculate the percentages as follows:(A) % who scored between 46 and 106:Total marks: 121 - 30 = 90Students between 46 and 106: 106 - 46 = 60Then,60/90 × 1002/3 × 10066.66Rounding off: 67% approx(B) % who scored less than 46:Total marks: 121 - 30 = 90Students who scored less than 46: 46 - 31 = 15Then,15/90 × 10016.66Rounding off: 17% approx(C) % who scored between 61 and 91:Total marks: 121 - 30 = 90Students between 61 and 91: 91 - 61 = 30Then,30/90 × 1001/3 × 10066.6633.33Rounding off: 33% approx(D) % who scored between 76 and 121:Total marks: 121 - 30 = 90Students between 76 and 121: 121 - 76 = 45Then,45/90 × 10050%Therefore, using percentages, the answer to all the subparts are shown:(A) % who scored between 46 and 106: 67% approx(B) % who scored less than 46: 17% approx(C) % who scored between 61 and 91: 33% approx(D) % who scored between 76 and 121: 50%Know more about percentages here:https://brainly.com/question/9553743#SPJ13