Write an equation for line L in point-slope form and slope-intercept form?
L is perpendicular to y=5x
Write an equation for the line L in point - slope form

The linear equation in the slope-intercept is:y = (-1/5)*x  - 26/5And it can be written as:y = (-1/5)*(x + 1) - 5How to find the equation for line L?We can write the equation for line L as:y = a*x +bWhere a is the slope and b is the y-intercept.Two lines are perpendicular if the product between the slopes is equal to -1.So if we want our line to be perpendicular to y= 5x, then we must have:a*5 = -1a = -1/5So our line is something like:y = (-1/5)*x + bAnd the line passes through (-1, -5), replacing these values:-5 = (-1/5)*-1 + b-5 = 1/5 + b-5 - 1/5 = b-26/5 = bThe linear equation is:y = (-1/5)*x  - 26/5Learn more about linear equations:https://brainly.com/question/1884491#SPJ1