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y = x - 6 is the equation of line parallel to x - y = 3 and passes through (2,-4).What is the equation of line that passes through the given point and parallel to the given equation?The equation of line is expressed as;y = mx + bThe point-slope formula is expressed as;y - y₁ = m( x - x₁ )Where m is slope and b is the y-intercept.Given the data in the question;Equation: x - y = 3Point: (2,-4)x = 2y = -4First, reorder the given equation in slope-intercept form and determine the slope.x - y = 3x = 3 + y3 + y = xy = x - 3Hence,The slope m = 1To find the line parallel to the equation, the slope must be equal.Find the line using point-slope formula.y - y₁ = m( x - x₁ )Plug in slope m = 1 and point: (2,-4)y - ( -4 ) = (1)( x - 2 )Simplify and convert to slope intercept form.y + 4 = x - 2y = x - 2 - 4y = x - 6Therefore, the equation of the line is y = x - 6.Learn more about equation of line here: brainly.com/question/2564656#SPJ1