Suppose 57% of the doctors in a hospital are surgeons.
If a sample of 465 doctors is selected, what is the probability that the sample proportion of surgeons will differ from the population proportion by greater than 6%? Round your answer to four decimal places.

The probability that the proportion of surgeons will differ from the population proportion by greater than 6%-22.22%How to solve for the probabilityP of 6%= P (p > 0.06)we would have to use the formula that is given below[tex]P[z > \frac{p-P}{\sqrt{} \frac{PQ}{n} }[/tex]where we have n = 465p = 6%P = 0.57Q = 1 - 0.57 = 0.43We would have to put the values into the equation that we have here as: 0.06 - 0.057 = -0.510.57 x 0.43 / 465 = 0.000527√0.000527 = 0.022956The probability =  -0.51 /  0.022956= -22.22%Read more on probability here: https://brainly.com/question/23286309#SPJ1