A person invested $440 in an account growing at a rate allowing the money to double every 8 years. How long, to the nearest tenth of a year would it take for the value of the account to reach $2,860?

The time that It would take  for the value of the account to reach $2,860 is; 21.6 yearsHow to solve compound interest problems?We are told that a person invested $440 in an account growing at a rate allowing the money to double every 8 years. Thus, the account balance can be modeled by the equation;A = 440(2)^(t/8) where;A is final amount t is in yearsWe want to find t when A = 2860. Thus;2860 = 440(2^(t/8))divide both sides by 440 to get;6.5 = 2^(t/8)log(6.5) = (t/8)log(2)t = 8 * log(6.5)/log(2) t ≈ 21.604Read more about compound interest at; https://brainly.com/question/24924853#SPJ1