Suppose that the maximum weight that a certain type of rectangular beam can support varies inversely as its length and jointly as its width and the square of its height. Suppose also that a beam 5 inches wide, 2 inches high, and 10 feet long can support a maximum of 8 tons. What is the maximum weight that could be supported by a beam that is 6 inches wide, 2 inches high, and 24 feet long?

The maximum weight that could be supported by a beam that is 6 inches wide, 2 inches high, and 24 feet long is 3.33.How to find the maximum weight ?G = C×(w×h²/l) Where,C = constantC = G×l/(w²h²)Weight (w) = 6 inHeight (h) = 2 inLength (l)= 10 ftMaximum ton (G) = 8 tC = 8×10/(6×2²)C = 80/24C = 10/3G = (10/3)×(w×h²/l)So, Maximum weight G = (10/3)×(6×2²/24)G = 10/3 tG = 3.33 tonesThe maximum weight is 3.33 tones.Learn more about maximum weight here: https://brainly.com/question/17031320#SPJ1