A 1,286-kg car is skidding to a stop along a horizontal surface. The car decelerates from 26.9 m/s to rest in 9.36 seconds. How far did the car skid before coming to rest?

Answer:Explanation:Given:M = 1 260 kgV₀ = 26.9 m/sV = 0 m/sΔt = 9.36 s___________L - ?1)Vehicle acceleration:a = (V - V₀) / Δt )  = (0 - 26.9) / 9.36  ≈ - 2.87 m/s²2)Braking distance of the car:L = (V² - V₀²) / (2·a)L = ( 0² - 26.9²) / (2·(-2.87)) ≈ 121 m