The volume V of a fixed amount of a gas varies directly as the temperature T and inversely as the pressure P. Suppose that V = 70 cm^3 when T = 420 kelvin and P = 18 kg/cm^2. Find the pressure when T = 140 kelvin and V = 60 cm^3.

The pressure of the gas is 7kg/cm^2How to determine the pressure of the gas?Joint Variation is a situation in which the value of one variable depends on two, or more, other variables when the other variables are held constantGiven that: The volume V of a fixed amount of a gas varies directly as the temperature T and inversely as the pressure P. This can be written as:VαT and Vα 1/P Combining the two relations gives:Thus Vα T/P  V = kT/P        (where k is a constant)​PV=kTk = ​PV/T​P =kT/VGiven: V = 70 cm^3 when T = 420 kelvin and P = 18 kg/cm^2k = 18×70 / 420 =  1260/420 =3Given: T = 140 kelvin and V = 60 cm^3. Find the pressure​P = kT/VP = 3×140/60 = 420/60 = 7kg/cm^2Therefore, the pressure when T = 140 kelvin and V = 60 cm^3 is 7kg/cm^2Learn more about joint variation on:https://brainly.com/question/11613758#SPJ1