A small town has two local high schools. High School A currently has 850 students and is projected to grow by 45 students each year. High School B currently has 1000 students and is projected to grow by 35 students each year. Let AA represent the number of students in High School A in tt years, and let BB represent the number of students in High School B after tt years. Write an equation for each situation, in terms of t,t, and determine how many students would be in each high school in the year they are projected to have the same number of students.

Answer: An equation for each situation, in terms of t, is y = 850e^45t andy = 1000e^35tStep-by-step explanation:The required equation will be in the form y = Ae^ktwhere:k is the growth constantA represents the number of students in High School A in t years.B represents the number of students in High School B after t years.If High School A currently has 850 students and is projected to grow by 35 students each year, hence;A = 850k = 45 (growth factor)Substituting into the formula, we will have:y = 850e^45tIf High School B currently has 700 students and is projected to grow by 60 students each year, hence;A = 1000k = 35 (growth factor)Substituting into the formula, we will have:y = 1000e^35tAn equation for each situation, in terms of t, is y = 850e^45t andy = 1000e^35t