Calculate the height (in m) of a cliff if it takes 2.41 s for a rock to hit the ground when it is thrown straight up from the cliff with an initial velocity of 8.14 m/s. (Enter a number.)How long (in s) would it take to reach the ground if it is thrown straight down with the same speed? (Enter a number.)

The height of the cliff is 7.57m and the time to reach the ground when thrown straight down is 0.814sWhat is motion under gravity?Motion under gravity refers to the movement of an object whose vertical motion is affected by the presence of gravity. The force that attracts objects downwards is GRAVITY. In fact, gravity works towards the centre of the Earth. When an object is moving upward,it is moving against gravity and when it is moving down it is moving with gravity.from equation of motionH= ut-1/2gt^2( the object is moving upward)where h is the height of the cliff and u is the initial velocity and g is acceleration due to gravity(g=10ms^-2).therefore h= 8.14×2.41-(1/2×10×2.41)= 19.62-12.05h= 7.57mwhen the object is thrown Down, V = u + gtu will be 0 at top before coming downV = gtt= 8.14/10= 0.814slearn more about motion under gravity fromhttps://brainly.com/question/88039#SPJ1