A line passes through points at (9, 5) and
(4, 3). What is the slope of the line
perpendicular to this line? (Lesson 3-8)
![[SOLVED] A line passes through points at (9, 5) and
(4, 3). What is the slope of the line
perpendicular to this line? (Lesson 3-8)](https://us-static.z-dn.net/files/da1/dada59cb42dc11f3c57a89a46014610d.png "[SOLVED] A line passes through points at (9, 5) and
(4, 3). What is the slope of the line
perpendicular to this line? (Lesson 3-8)")
Suggested Answer
Answer: Slope- 2/5 or 0.4Step-by-step explanation:Slope (m) = ΔYΔX= 25= 0.4θ = arctan( ΔY ) + 180°ΔX= 201.80140948635°ΔX = 4 – 9 = -5ΔY = 3 – 5 = -2Distance (d) = √ΔX2 + ΔY2 = √29 = 5.3851648071345Equation of the line:y = 0.4x + 1.4ory = 2 x5 + 75When x=0, y = 1.4When y=0, x = -3.5
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