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Consider the recursively defined function below.
f(1) = = 10
f(n) 2.2 f(n-1), for n = 2, 3, 4, ...
Create the first five terms of the sequence defined by the given function.

The first five terms of the sequence defined by the given function are f(1) = 10 f(2) = 22  f(3) = 48.4 f(4) = 106.48 and f(5) = 234.256.What is a sequence?A collection of events or items that occur one after the other in a specific order is referred to as a sequence.Here, we haveGiven the function is f(n) = 2.2 [ f(n-1) ] Here, f(1) = 10 then we have to create the first five terms of the sequence defined by the function.Since f(1) = 10f(2) = 2.2 [ f (2-1) ] = 2.2× [ f (1) ]     = 2.2 × 10 = 22f (3) = 2.2 [ f (3-1)] = 2.2 × [ f (2) ]        = 2.2 × 22 = 48.4f(4)  = 2.2 [ f(4-1) ] = 2.2× [ f(3)]        = 2.2 × 48.4 = 106.48f(5)  = 2.2 [ f(5-1) ] = 2.2× [ f(4)]         2.2× 106.48 = 234.256Hence the first five terms of the sequence defined by the given function are f(1) = 10 f(2) = 22  f(3) = 48.4 f(4) = 106.48 and f(5) = 234.256.To learn more about the sequence from the given linkhttps://brainly.com/question/29327579#SPJ1