I have an unknown volume of gas held at a temperature of 126 K in a container with a pressure of 31 atm. If by increasing the temperature to 209 K and decreasing the pressure to 19 atm causes the volume of the gas to be 9.4 liters, how many liters of gas did I start with?

The volume that was started with if the temperature of 126 K in a container with a pressure of 31 atm is 3.47L. How to calculate volume?The volume of a gas can be calculated using the combined gas law equation as follows:P₁V₁/T₁ = P₂V₂/T₂Where;P₁ = initial pressureV₁ = final pressureT₁ = initial temperatureP₂ = final pressureV₂ = final volumeT₂ = final temperatureAccording to this question, an unknown volume of gas held at a temperature of 126K in a container with a pressure of 31 atm. If by increasing the temperature to 209 K and decreasing the pressure to 19 atm causes the volume of the gas to be 9.4 liters, the initial volume is calculated as follows:31 × V₁/126 = 19 × 9.4/2090.246V = 178.6/2090.246V = 0.854V = 3.47LTherefore, 3.47L is the volume of the gas that started. Learn more about volume at: https://brainly.com/question/12357202#SPJ1