Write a polynomial f (x) that satisfies the given conditions.
Degree 3 polynomial with integer coefficients with zeros 7i and 9/5

If the degree of the polynomial is 3 with zeros 7i and 9/5, then the polynomial f(x) = [tex]5x^3-9x^2+245x-441[/tex]The zeros of the polynomial = 7i and 9/5Here the degree of polynomial is 3, therefore there will be three zeros in polynomial, here only 2 zeros are given. We have to find the third zero of the polynomial. Here one of the polynomial is complex number, therefore another zero will be the conjugate of the complex zeroTherefore the equation will be(x+7i)(x-7i)(5x-9) = 0We have to solve the equation([tex]x^2[/tex] -7ix+7ix+49)(5x-9) = 0([tex]x^2[/tex] + 49)(5x - 9) = 0[tex]5x^3-9x^2+245x-441 =0[/tex]Thereforef(x) = [tex]5x^3-9x^2+245x-441[/tex]Hence, if the degree of the polynomial is 3 with zeros 7i and 9/5, then the polynomial f(x) = [tex]5x^3-9x^2+245x-441[/tex]Learn more about polynomial herebrainly.com/question/28652768#SPJ1