Accepted Answer
The pH of the 3.9M of pottasium fluoride is 0.591. How to calculate pH?pH of a solution can be described as the figure expressing the acidity or alkalinity of a solution on a logarithmic scale on which 7 is neutral, lower values are more acid and higher values more alkaline.The pH of a solution can be calculated by using the following expression:pH = -log {H}Where;H = hydrogen ion concentrationAccording to this question, a 3.9 M potassium fluoride is given. The pH can be calculated as follows:pH = - log {3.9}pH = -0.591Therefore, the pH of the solution is 0.591Learn more about pH at: https://brainly.com/question/11300720#SPJ1
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