11. Using the equation: y + 2 = 3(x - 1).
a) Identify the slope and y-intercept.
b) Graph the equation.
c) Does the point (0,0) satisfy the equation?
Justify your answer.

For the given equation, the slope is 3 and the y-intercept is -5. From the graph, it is possible to see that the point (0,0) does not satisfy the equation.Linear FunctionAn equation can be represented by a linear function. The standard form for the linear equation is: y= mx+b , for example, y=x+19. A line equation also can be represented by the point-slope form: [tex](y-y_1)=m(x-x_1)[/tex].m= the slope.[tex](x_1,y_1)[/tex]= the coordinate of a point.For the given example: m=1 and b=19.The question gives: y + 2 = 3(x - 1). Therefore, y + 2 = 3(x - 1)y=3x-3-2y=3x-5 Letter A - Identify the slope and y-interceptIf y=3x-5 . Here, you have a standard form of a linear equation y=mx+b. Where:m= the slope. It can be calculated for Δy/Δx.b= the constant term that represents the y-interceptThus, the slope is 3 and the y-intercept is -5.Letter B - Graph the equation.For this, you should do a table with pointsx     y= 3x-5-2   y=3*(-2)-5=-6-5= -11-1    y=3*(-1)-5=-3-5= -80   y=3*(0)-5=0-5= -51    y=3*(1)-5=3-5= -22    y=3*(2)-5=6-5= 1Draw a graph from these points, see the attached image.Letter C - Does the point (0,0) satisfy the equation?The point (0,0) does not satisfy the equation because when x=0 because y is different than zero (0). See below.y= 3x-5, for x=0y=3*0-5y=0-5y=-5Read more about the linear equations here:brainly.com/question/2030026#SPJ1