Suppose a large consignment of compact discs contained 13% defectives.
If a sample of size 329 is selected, what is the probability that the sample proportion will differ from the population proportion by more than 3%? Round your answer to four decimal places.

The probability that the sample proportion will differ from the population proportion by more than 3% is 0.8948How to calculate the probability?The requirement to solve the probability between z-values is to know that the probability between the z-values is the difference between the probability of the greatest z-value and the lowest z-value.In this case, the sample proportion:= ✓[p(1 - p)/n]= ✓(0.13 × 0.87)/329= 0.01854.The probability will be:P(-0.03 / 0.01854) < z < (0.03 / 0.01854)P(-1.62 < z < 1.62)Looking at the z table, the probability is 0.08948Learn more about probability on:brainly.com/question/24756209#SPJ1