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From the given set of equation the one which has same solution as x² + 4x + 13 = -10 is given by (x+2)² = -19.As given in the question,Given equation is equal to:x² + 4x + 13 = -10Simplify it we get,x² + 4x + 13 +10 =0⇒ x² + 4x + 23 =0 ___(1)General quadratic equation is ax² + bx + c =0a = 1 , b =4 , c =23Simplify the given options we have:a. (x+2)² = -19⇒ x² + 4x + 4 = -19⇒ x² + 4x + 4 + 19 =0⇒ x² + 4x + 23 =0Has same solution as given one.b. (x-2)² = -27⇒ x² -4x + 4 +27 =0⇒x² -4x +31 =0'b' and 'c' value are differentNot have same solution.c. (x-2)² =-19⇒ x² -4x + 4 +19 =0⇒x² -4x +23 =0'b' value is different.Not have same solution.d. (x+2)² = -27⇒ x² +4x + 4 +27 =0⇒x² +4x +31 =0 'c' value is differentNot have same solution.Therefore, from the given set of equation the one which has same solution as x² + 4x + 13 = -10 is given by (x+2)² = -19.The complete question is:Which equation has the same solution as x² + 4x + 13 = -10?a. (x+2)² = -19b. (x-2)² = -27c. (x-2)² =-19d. (x+2)² = -27Learn more about equation herebrainly.com/question/10413253#SPJ1