Write the equation of the line with a slope of 3/2that contains the point ( — 4, − 2).

The equation of line with a slope of 3/2 which passes through point (-4,-2) is y = (3/2)x + 4.What is the equation of line with the given point and slope?The equation of line is expressed as;y = mx + bWhere m is slope and b is y-intercept.Given the data in the question;Point (-4, -2 )x = -4y = -2Slope m = 3/2First, we determine the y-intercept 'b'.Plug the point and slope slope into the equation of line formula and solve for b.y = mx + b-2 = (3/2)(-4) + b-2 = (3)(-2) + b-2 = -6 + bb = -2 + 6b = 4Now, plug the slope and y-intercept into y = mx + b to determine the equation of the line.y = mx + by = (3/2)x + 4Therefore, the equation of the line is y = (3/2)x + 4.Learn more about  equation of line here: brainly.com/question/2564656#SPJ1