A hexagon has exterior angle measures of (7n + 3), (10n-17)°,
(8n - 16), (4n+17), (-n + 16), and (5n - 6)°.
Find the value of n.

Using the sum of exterior angle, the value of n is 11.In the given question,A hexagon has exterior angle measures of (7n + 3), (10n-17), (8n - 16), (4n+17), (-n + 16), and (5n - 6)°.We have to find the value of n.As we know that the sum of exterior angle of any polygon is equal to 360°.As the given measures are (7n + 3), (10n-17), (8n - 16), (4n+17), (-n + 16), and (5n - 6)°.So we can find the value of n by adding the all measures.So the expression should be(7n + 3) + (10n-17) + (8n - 16) + (4n+17) + (-n + 16) + (5n - 6)° = 360°Simplifying the bracket.7n + 3 + 10n-17 + 8n - 16 + 4n+17 - n + 16 + 5n - 6 = 360°Solving the expression by solving the same term (7n+10n+8n+4n-n+5n)+(3-17-16+17+16-6)= 360°33n-3 = 360°Add 3 on both side33n-3+3 = 360°+333n = 357°Divide by 33 on both side33/33 n= 363°/33n = 11Hence, the value of n is 11.To learn more about sum of exterior angle link is herebrainly.com/question/1983075#SPJ1